Many projects of hardware engineers are completed on perforated boards, but there is a phenomenon that the positive and negative poles of the power supply are accidentally reversed, causing many electronic components to be burned, and even the entire board is scrapped, and another piece has to be soldered , do you know any good way to solve it?
First of all, carelessness is unavoidable, although it is only to distinguish the positive and negative wires, one red and one black. We may not make a mistake in connecting the line once; it will not make a mistake in connecting the line 10 times, but 1000 times? What about 10000 times? It’s hard to say at this time, due to our carelessness, some electronic components and chips were burnt out, the main reason is that the components were broken down due to excessive current, so measures must be taken to prevent reverse connection.
1. Diode series anti-reverse connection protection circuit
A forward diode is connected in series at the input terminal of the positive power supply to make full use of the characteristics of the forward conduction and reverse cutoff of the diode. Normally, the diode conducts and the board works.
When the power supply is reversed, the diode is cut off, the power supply cannot form a loop, and the circuit board does not work, which can effectively prevent the problem of reversed power supply. But there will be a diode voltage drop, and it is also important to choose the corresponding diode according to the supply current.
2. Rectifier bridge type anti-reverse connection protection circuit
Use a rectifier bridge to change the power input into a non-polar input, no matter whether the power is connected positively or reversely, the circuit board will work normally.
The above uses diodes for anti-reverse treatment. If silicon diodes are used, the voltage drop will be about 0.6, 0.8V, and germanium diodes will also have a voltage drop of about 0.2, 0.4V. If the voltage drop is too large, you can use MOS tubes for anti-reverse treatment. The voltage drop of the MOS tube is very small, up to a few milliohms, and the voltage drop is almost negligible.
3. MOS tube anti-reverse protection circuit
Because of factors such as the improvement of the MOS tube process and its own properties. Most of its conduction internal resistance is milliohm level or even smaller, so the loss caused by the voltage drop and power consumption of the circuit is very small, or even negligible, so it is recommended to choose a MOS tube to protect the circuit Way.
(1) NMOS protection
As shown in the figure below: at the moment of power-on, the parasitic diode of the MOS tube is turned on, and the system forms a loop. The potential of the source S is about 0.6V, and the potential of the gate G is VBAT, and the turn-on voltage of the MOS tube is extremely: UGS = VBAT - Vs, the gate shows a high level, the DS of the NMOS is turned on, the parasitic diode is short-circuited, and the system forms a loop through the DS of the NMOS.
If the power supply is reversed, the conduction voltage of the NMOS is 0, the NMOS is cut off, the parasitic diode is reversed, and the circuit is disconnected, thereby forming a protection.
(2) PMOS protection
As shown in the figure below: at the moment of power-on, the parasitic diode of the MOS tube is turned on, and the system forms a loop. The potential of the source S is about Vbat-0.6V, while the potential of the gate G is 0, and the turn-on voltage of the MOS tube is extremely: UGS = 0 -(Vbat-0.6), the gate is low level, the DS of the PMOS is turned on, the parasitic diode is short-circuited, and the system forms a loop through the DS of the PMOS.
If the power supply is reversed, the conduction voltage of the NMOS is greater than 0, the PMOS is cut off, the parasitic diode is reversed, and the circuit is disconnected, thereby forming a protection.
If the power supply is reversed, the conduction voltage of the NMOS is greater than 0, the PMOS is cut off, the parasitic diode is reversed, and the circuit is disconnected, thereby forming a protection.
Note: The NMOS transistor connects DS to the negative pole, the PMOS transistor DS connects to the positive pole, and the direction of the parasitic diode faces the current direction of the correct connection.
The connection of the D pole and the S pole of the MOS tube: when using an N-channel MOS tube, the current generally enters from the D pole and flows out from the S pole, while the PMOS enters from the S pole and flows out from the D pole. In the circuit, it is just the opposite, and the voltage condition for the MOS transistor to be turned on is met through the conduction of the parasitic diode. As long as an appropriate voltage is established between the G and S poles, the MOS tube will be fully turned on. After it is turned on, it is like a switch is closed between D and S, and the current is the same resistance from D to S or S to D.
In practical applications, the G pole is generally connected in series with a resistor. In order to prevent the MOS tube from being broken down, a Zener diode can also be added. The capacitor connected in parallel to the voltage divider resistor has a soft start effect. At the moment when the current starts to flow, the capacitor is charged, and the voltage of the G electrode is gradually established.
For PMOS, compared with NOMS, VGS is required to be greater than the threshold voltage. Since its turn-on voltage can be 0, the voltage difference between DS is not large, which is more advantageous than NMOS.
4. Fuse protection
For many common electronic products, after disassembly, you can see that the power supply has a fuse. When the power supply is reversed and there is a short circuit in the circuit, the fuse will be blown due to a large current to protect the circuit. However, this method it is more troublesome to repair and replace. But you can choose to buy resettable fuses.
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